What are the solutions to the equation 2y^2-6y+8=0 ?

The solutions to the equation 2y^2-6y+8=0 are y= 3/2+i(sqrt(7))/2 ,y= 3/2-i(sqrt(7))/2

Find the zeros of 2y^2-6y+8=0

The zeros of 2y^2-6y+8=0 are y= 3/2+i(sqrt(7))/2 ,y= 3/2-i(sqrt(7))/2

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2 y^{2} - 6 y + 8 = 0

y = \frac{3}{2} + i \frac{7}{2}, y = \frac{3}{2} - i \frac{7}{2}

Solution steps

2 y^{2} - 6 y + 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 8 : 27 i

y_{1, 2} = \frac{- ( - 6 ) \pm 2 7 i}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 2}, y_{2} = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 2}

y = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 2} : \frac{3}{2} + i \frac{7}{2}

y = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 2} : \frac{3}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

y = \frac{3}{2} + i \frac{7}{2}, y = \frac{3}{2} - i \frac{7}{2}

x^{2} = 40 - 3 x

4 x^{2} - 40 x = - 24

3 x^{2} - 17 x + 24 = 0

x^{2} - 11 x + 8 = 0

y^{2} = - 18 y

What are the solutions to the equation 2y^2-6y+8=0 ?
The solutions to the equation 2y^2-6y+8=0 are y= 3/2+i(sqrt(7))/2 ,y= 3/2-i(sqrt(7))/2
Find the zeros of 2y^2-6y+8=0
The zeros of 2y^2-6y+8=0 are y= 3/2+i(sqrt(7))/2 ,y= 3/2-i(sqrt(7))/2