What are the solutions to the equation y^2=-18y ?

The solutions to the equation y^2=-18y are y=0,y=-18

Find the zeros of y^2=-18y

The zeros of y^2=-18y are y=0,y=-18

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y^{2} = - 18 y

y = 0, y = - 18

Solution steps

y^{2} = - 18 y

Move

18 y

to the left side

y^{2} + 18 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 0 = 18

y_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 18 + 18}{2 \cdot 1}, y_{2} = \frac{- 18 - 18}{2 \cdot 1}

y = \frac{- 18 + 18}{2 \cdot 1} : 0

y = \frac{- 18 - 18}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

y = 0, y = - 18

25 h^{2} + 80 h = - 61

(x + 5)^{2} = 13

8 x^{2} = 6 x

x^{2} - 10 x = - 24

4 x^{2} - 10 x + 25 = 0

What are the solutions to the equation y^2=-18y ?
The solutions to the equation y^2=-18y are y=0,y=-18
Find the zeros of y^2=-18y
The zeros of y^2=-18y are y=0,y=-18