What are the solutions to the equation 25h^2+80h=-61 ?

The solutions to the equation 25h^2+80h=-61 are h=(-8+sqrt(3))/5 ,h=-(8+sqrt(3))/5

Find the zeros of 25h^2+80h=-61

The zeros of 25h^2+80h=-61 are h=(-8+sqrt(3))/5 ,h=-(8+sqrt(3))/5

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25 h^{2} + 80 h = - 61

h = \frac{- 8 + 3}{5}, h = - \frac{8 + 3}{5}

Decimal Notation

h = - 1.25358 \dots, h = - 1.94641 \dots

Solution steps

25 h^{2} + 80 h = - 61

Move

61

to the left side

25 h^{2} + 80 h + 61 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 25 \cdot 61}{2 \cdot 25}

8 0^{2} - 4 \cdot 25 \cdot 61 = 103

h_{1, 2} = \frac{- 80 \pm 10 3}{2 \cdot 25}

Separate the solutions

h_{1} = \frac{- 80 + 10 3}{2 \cdot 25}, h_{2} = \frac{- 80 - 10 3}{2 \cdot 25}

h = \frac{- 80 + 10 3}{2 \cdot 25} : \frac{- 8 + 3}{5}

h = \frac{- 80 - 10 3}{2 \cdot 25} : - \frac{8 + 3}{5}

The solutions to the quadratic equation are:

h = \frac{- 8 + 3}{5}, h = - \frac{8 + 3}{5}

(x + 5)^{2} = 13

8 x^{2} = 6 x

x^{2} - 10 x = - 24

4 x^{2} - 10 x + 25 = 0

x, 6 x^{2} + x - 1 = 0

What are the solutions to the equation 25h^2+80h=-61 ?
The solutions to the equation 25h^2+80h=-61 are h=(-8+sqrt(3))/5 ,h=-(8+sqrt(3))/5
Find the zeros of 25h^2+80h=-61
The zeros of 25h^2+80h=-61 are h=(-8+sqrt(3))/5 ,h=-(8+sqrt(3))/5