What are the solutions to the equation roots x^2+x+10 ?

The solutions to the equation roots x^2+x+10 are x=-1/2+i(sqrt(39))/2 ,x=-1/2-i(sqrt(39))/2

Find the zeros of roots x^2+x+10

The zeros of roots x^2+x+10 are x=-1/2+i(sqrt(39))/2 ,x=-1/2-i(sqrt(39))/2

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roots

x^{2} + x + 10

x = - \frac{1}{2} + i \frac{39}{2}, x = - \frac{1}{2} - i \frac{39}{2}

Solution steps

x^{2} + x + 10

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 10 : 39 i

x_{1, 2} = \frac{- 1 \pm 39 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 39 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 39 i}{2 \cdot 1}

x = \frac{- 1 + 39 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{39}{2}

x = \frac{- 1 - 39 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{39}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{39}{2}, x = - \frac{1}{2} - i \frac{39}{2}

2 y^{2} - 6 y + 5 = 0

x^{2} - 30 x - 100 = 0

3 \cdot 0.0008 \cdot x^{2} - 4.4 x + 1400 = 0

5 x (x - 1) = 2 (x + 3)

5 = - 16 t^{2} + 22 t + 6

What are the solutions to the equation roots x^2+x+10 ?
The solutions to the equation roots x^2+x+10 are x=-1/2+i(sqrt(39))/2 ,x=-1/2-i(sqrt(39))/2
Find the zeros of roots x^2+x+10
The zeros of roots x^2+x+10 are x=-1/2+i(sqrt(39))/2 ,x=-1/2-i(sqrt(39))/2