What are the solutions to the equation 2x^2-9x+35=0 ?

The solutions to the equation 2x^2-9x+35=0 are x= 9/4+i(sqrt(199))/4 ,x= 9/4-i(sqrt(199))/4

Find the zeros of 2x^2-9x+35=0

The zeros of 2x^2-9x+35=0 are x= 9/4+i(sqrt(199))/4 ,x= 9/4-i(sqrt(199))/4

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2 x^{2} - 9 x + 35 = 0

x = \frac{9}{4} + i \frac{199}{4}, x = \frac{9}{4} - i \frac{199}{4}

Solution steps

2 x^{2} - 9 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 35}{2 \cdot 2}

Simplify

(- 9)^{2} - 4 \cdot 2 \cdot 35 : 199 i

x_{1, 2} = \frac{- ( - 9 ) \pm 199 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 199 i}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 199 i}{2 \cdot 2}

x = \frac{- ( - 9 ) + 199 i}{2 \cdot 2} : \frac{9}{4} + i \frac{199}{4}

x = \frac{- ( - 9 ) - 199 i}{2 \cdot 2} : \frac{9}{4} - i \frac{199}{4}

The solutions to the quadratic equation are:

x = \frac{9}{4} + i \frac{199}{4}, x = \frac{9}{4} - i \frac{199}{4}

x^{2} - 7 x = x - 13

4 x^{2} = 4 x + 1

5 x^{2} = - 45 x

0 = - 2 x^{2} + 3 x - 1

3 x^{2} = 12 - 16 x

What are the solutions to the equation 2x^2-9x+35=0 ?
The solutions to the equation 2x^2-9x+35=0 are x= 9/4+i(sqrt(199))/4 ,x= 9/4-i(sqrt(199))/4
Find the zeros of 2x^2-9x+35=0
The zeros of 2x^2-9x+35=0 are x= 9/4+i(sqrt(199))/4 ,x= 9/4-i(sqrt(199))/4