What are the solutions to the equation 2(x+4)(3x-5)=6 ?

The solutions to the equation 2(x+4)(3x-5)=6 are x=(-7+5sqrt(13))/6 ,x=-(7+5sqrt(13))/6

Find the zeros of 2(x+4)(3x-5)=6

The zeros of 2(x+4)(3x-5)=6 are x=(-7+5sqrt(13))/6 ,x=-(7+5sqrt(13))/6

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2 (x + 4) (3 x - 5) = 6

x = \frac{- 7 + 5 13}{6}, x = - \frac{7 + 5 13}{6}

Decimal Notation

x = 1.83795 \dots, x = - 4.17129 \dots

Solution steps

2 (x + 4) (3 x - 5) = 6

Expand

2 (x + 4) (3 x - 5) : 6 x^{2} + 14 x - 40

6 x^{2} + 14 x - 40 = 6

Move

6

to the left side

6 x^{2} + 14 x - 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 6 ( - 46 )}{2 \cdot 6}

1 4^{2} - 4 \cdot 6 (- 46) = 1013

x_{1, 2} = \frac{- 14 \pm 10 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 14 + 10 13}{2 \cdot 6}, x_{2} = \frac{- 14 - 10 13}{2 \cdot 6}

x = \frac{- 14 + 10 13}{2 \cdot 6} : \frac{- 7 + 5 13}{6}

x = \frac{- 14 - 10 13}{2 \cdot 6} : - \frac{7 + 5 13}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 5 13}{6}, x = - \frac{7 + 5 13}{6}

x^{2} - 6 x + 5

x^{2} + 24 + 140 = 0

(x - 3) (x + 9) = 0

3 t^{2} - 5 t - 2 = 0

- 4 x^{2} + 24 x - 41

What are the solutions to the equation 2(x+4)(3x-5)=6 ?
The solutions to the equation 2(x+4)(3x-5)=6 are x=(-7+5sqrt(13))/6 ,x=-(7+5sqrt(13))/6
Find the zeros of 2(x+4)(3x-5)=6
The zeros of 2(x+4)(3x-5)=6 are x=(-7+5sqrt(13))/6 ,x=-(7+5sqrt(13))/6