What are the solutions to the equation 3t^2-5t-2=0 ?

The solutions to the equation 3t^2-5t-2=0 are t=2,t=-1/3

Find the zeros of 3t^2-5t-2=0

The zeros of 3t^2-5t-2=0 are t=2,t=-1/3

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3 t^{2} - 5 t - 2 = 0

t = 2, t = - \frac{1}{3}

Decimal Notation

t = 2, t = - 0.33333 \dots

Solution steps

3 t^{2} - 5 t - 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 2) = 7

t_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 3}, t_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 3}

t = \frac{- ( - 5 ) + 7}{2 \cdot 3} : 2

t = \frac{- ( - 5 ) - 7}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

t = 2, t = - \frac{1}{3}

- 4 x^{2} + 24 x - 41

- 6 x^{2} = 72

c^{2} + c - 19 = 4 c

- x^{2} + 6 x = 10

y, x^{2} - x (y - 2) - 3 y = 0

What are the solutions to the equation 3t^2-5t-2=0 ?
The solutions to the equation 3t^2-5t-2=0 are t=2,t=-1/3
Find the zeros of 3t^2-5t-2=0
The zeros of 3t^2-5t-2=0 are t=2,t=-1/3