What are the solutions to the equation solvefor x,x^2-5x+6=x+3 ?

The solutions to the equation solvefor x,x^2-5x+6=x+3 are x=3+sqrt(6),x=3-sqrt(6)

Find the zeros of solvefor x,x^2-5x+6=x+3

The zeros of solvefor x,x^2-5x+6=x+3 are x=3+sqrt(6),x=3-sqrt(6)

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x, x^{2} - 5 x + 6 = x + 3

x = 3 + 6, x = 3 - 6

Decimal Notation

x = 5.44948 \dots, x = 0.55051 \dots

Solution steps

x^{2} - 5 x + 6 = x + 3

Move

3

to the left side

x^{2} - 5 x + 3 = x

Move

x

to the left side

x^{2} - 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 3 = 26

x_{1, 2} = \frac{- ( - 6 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 6}{2 \cdot 1} : 3 + 6

x = \frac{- ( - 6 ) - 2 6}{2 \cdot 1} : 3 - 6

The solutions to the quadratic equation are:

x = 3 + 6, x = 3 - 6

- 14 s^{2} + 440 s - 3300 = 0

8 x^{2} - 8 x + 21 = 0

3 x^{2} - 2 x - 37 = 0

4 p^{2} - 7 p + 6 = 5

0 = 1 - x - x^{2}

What are the solutions to the equation solvefor x,x^2-5x+6=x+3 ?
The solutions to the equation solvefor x,x^2-5x+6=x+3 are x=3+sqrt(6),x=3-sqrt(6)
Find the zeros of solvefor x,x^2-5x+6=x+3
The zeros of solvefor x,x^2-5x+6=x+3 are x=3+sqrt(6),x=3-sqrt(6)