What are the solutions to the equation -3x^2-6x-4=0 ?

The solutions to the equation -3x^2-6x-4=0 are x=-1-i(sqrt(3))/3 ,x=-1+i(sqrt(3))/3

Find the zeros of -3x^2-6x-4=0

The zeros of -3x^2-6x-4=0 are x=-1-i(sqrt(3))/3 ,x=-1+i(sqrt(3))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} - 6 x - 4 = 0

x = - 1 - i \frac{3}{3}, x = - 1 + i \frac{3}{3}

Solution steps

- 3 x^{2} - 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) ( - 4 )}{2 ( - 3 )}

Simplify

(- 6)^{2} - 4 (- 3) (- 4) : 23 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 6 ) - 2 3 i}{2 ( - 3 )}

x = \frac{- ( - 6 ) + 2 3 i}{2 ( - 3 )} : - 1 - i \frac{3}{3}

x = \frac{- ( - 6 ) - 2 3 i}{2 ( - 3 )} : - 1 + i \frac{3}{3}

The solutions to the quadratic equation are:

x = - 1 - i \frac{3}{3}, x = - 1 + i \frac{3}{3}

y, x^{2} y + x y^{2} = 3 x

5 x^{2} + 13 x - 18 = 0

12 x^{2} + 24 x - 15 = 0

9 (3 x - 3)^{2} + 25 = 26

x^{2} - 3 x - 18 = 0

What are the solutions to the equation -3x^2-6x-4=0 ?
The solutions to the equation -3x^2-6x-4=0 are x=-1-i(sqrt(3))/3 ,x=-1+i(sqrt(3))/3
Find the zeros of -3x^2-6x-4=0
The zeros of -3x^2-6x-4=0 are x=-1-i(sqrt(3))/3 ,x=-1+i(sqrt(3))/3