What are the solutions to the equation 9(3x-3)^2+25=26 ?

The solutions to the equation 9(3x-3)^2+25=26 are x= 10/9 ,x= 8/9

Find the zeros of 9(3x-3)^2+25=26

The zeros of 9(3x-3)^2+25=26 are x= 10/9 ,x= 8/9

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9 (3 x - 3)^{2} + 25 = 26

x = \frac{10}{9}, x = \frac{8}{9}

Decimal Notation

x = 1.11111 \dots, x = 0.88888 \dots

Solution steps

9 (3 x - 3)^{2} + 25 = 26

Move

25

to the right side

9 (3 x - 3)^{2} = 1

Divide both sides by

9

(3 x - 3)^{2} = \frac{1}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 3 = \frac{1}{9} : x = \frac{10}{9}

Solve

3 x - 3 = - \frac{1}{9} : x = \frac{8}{9}

The solutions to the quadratic equation are:

x = \frac{10}{9}, x = \frac{8}{9}

x^{2} - 3 x - 18 = 0

- 2 x^{2} + 16 x = - 74

r^{2} + 4 r + 13

5 x^{2} + 10 x = 0

2 W^{2} - 5 W - 33 = 0

What are the solutions to the equation 9(3x-3)^2+25=26 ?
The solutions to the equation 9(3x-3)^2+25=26 are x= 10/9 ,x= 8/9
Find the zeros of 9(3x-3)^2+25=26
The zeros of 9(3x-3)^2+25=26 are x= 10/9 ,x= 8/9