What are the solutions to the equation x^2-4x+36=0 ?

The solutions to the equation x^2-4x+36=0 are x=2+4sqrt(2)i,x=2-4sqrt(2)i

Find the zeros of x^2-4x+36=0

The zeros of x^2-4x+36=0 are x=2+4sqrt(2)i,x=2-4sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 4 x + 36 = 0

x = 2 + 42 i, x = 2 - 42 i

Solution steps

x^{2} - 4 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 36 : 82 i

x_{1, 2} = \frac{- ( - 4 ) \pm 8 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 8 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 8 2 i}{2 \cdot 1} : 2 + 42 i

x = \frac{- ( - 4 ) - 8 2 i}{2 \cdot 1} : 2 - 42 i

The solutions to the quadratic equation are:

x = 2 + 42 i, x = 2 - 42 i

3 x^{2} - 4 x + 5 = 4

2 x^{2} + 5 x - 11 = 1

s^{2} + 14 s + 2

2 x^{2} - 11 x + 14

4 x^{2} - 20 x + 26 = 0

What are the solutions to the equation x^2-4x+36=0 ?
The solutions to the equation x^2-4x+36=0 are x=2+4sqrt(2)i,x=2-4sqrt(2)i
Find the zeros of x^2-4x+36=0
The zeros of x^2-4x+36=0 are x=2+4sqrt(2)i,x=2-4sqrt(2)i