What are the solutions to the equation sqrt(-1)=x^2+4 ?

The solutions to the equation sqrt(-1)=x^2+4 are

Find the zeros of sqrt(-1)=x^2+4

The zeros of sqrt(-1)=x^2+4 are

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- 1 = x^{2} + 4

Solution steps

- 1 = x^{2} + 4

Expand

- 1 : i

i = x^{2} + 4

Switch sides

x^{2} + 4 = i

Move

4

to the right side

x^{2} = i - 4

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 2, a = i - 4

∣ a ∣ = 17

ar g (a) = - arctan (\frac{1}{4}) + π

x = 17 (cos (\frac{- arctan ( \frac{1}{4} ) + π + 2 \cdot 0 π}{2}) + i sin (\frac{- arctan ( \frac{1}{4} ) + π + 2 \cdot 0 π}{2})), x = 17 (cos (\frac{- arctan ( \frac{1}{4} ) + π + 2 \cdot 1 π}{2}) + i sin (\frac{- arctan ( \frac{1}{4} ) + π + 2 \cdot 1 π}{2}))

Simplify

x^{2} = - 16

x^{2} + 8 x + 25 = 0

8 x^{2} + 9 = 313

16 x^{2} - 25 = 0

3 x^{2} + 18 = 15 x

What are the solutions to the equation sqrt(-1)=x^2+4 ?
The solutions to the equation sqrt(-1)=x^2+4 are
Find the zeros of sqrt(-1)=x^2+4
The zeros of sqrt(-1)=x^2+4 are