What are the solutions to the equation (4x)^2=l^2+l^2 ?

The solutions to the equation (4x)^2=l^2+l^2 are x= l/(2sqrt(2)),x=-l/(2sqrt(2))

Find the zeros of (4x)^2=l^2+l^2

The zeros of (4x)^2=l^2+l^2 are x= l/(2sqrt(2)),x=-l/(2sqrt(2))

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(4 x)^{2} = l^{2} + l^{2}

x = \frac{l}{2 2}, x = - \frac{l}{2 2}

Solution steps

(4 x)^{2} = l^{2} + l^{2}

Add similar elements:

l^{2} + l^{2} = 2 l^{2}

(4 x)^{2} = 2 l^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x = 2 l^{2} : x = \frac{l}{2 2}

Solve

4 x = - 2 l^{2} : x = - \frac{l}{2 2}

The solutions to the quadratic equation are:

x = \frac{l}{2 2}, x = - \frac{l}{2 2}

x^{2} + 42 = 13 x

11 x^{2} - 2 = 0

4 x^{2} - 18 x + 14 = 0

r^{2} = - 2

9 (x^{2} - 10) + 14 = - 12

What are the solutions to the equation (4x)^2=l^2+l^2 ?
The solutions to the equation (4x)^2=l^2+l^2 are x= l/(2sqrt(2)),x=-l/(2sqrt(2))
Find the zeros of (4x)^2=l^2+l^2
The zeros of (4x)^2=l^2+l^2 are x= l/(2sqrt(2)),x=-l/(2sqrt(2))