What are the solutions to the equation 5x^2+50x+125=0 ?

The solutions to the equation 5x^2+50x+125=0 are x=-5

Find the zeros of 5x^2+50x+125=0

The zeros of 5x^2+50x+125=0 are x=-5

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5 x^{2} + 50 x + 125 = 0

x = - 5

Solution steps

5 x^{2} + 50 x + 125 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 5 \cdot 125}{2 \cdot 5}

5 0^{2} - 4 \cdot 5 \cdot 125 = 0

x_{1, 2} = \frac{- 50 \pm 0}{2 \cdot 5}

x = \frac{- 50}{2 \cdot 5}

\frac{- 50}{2 \cdot 5} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

x^{2} + 9 x + 20 = - 3 x

3 a^{2} - 4 a - 5 = 0

5 x^{2} - 1 = - 4

x^{2} - 14 x + 65

(2 - x)^{2} + 1 = 0

What are the solutions to the equation 5x^2+50x+125=0 ?
The solutions to the equation 5x^2+50x+125=0 are x=-5
Find the zeros of 5x^2+50x+125=0
The zeros of 5x^2+50x+125=0 are x=-5