What are the solutions to the equation (2-x)^2+1=0 ?

The solutions to the equation (2-x)^2+1=0 are x=-i+2,x=i+2

Find the zeros of (2-x)^2+1=0

The zeros of (2-x)^2+1=0 are x=-i+2,x=i+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 - x)^{2} + 1 = 0

x = - i + 2, x = i + 2

Solution steps

(2 - x)^{2} + 1 = 0

Move

1

to the right side

(2 - x)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 - x = - 1 : x = - i + 2

Solve

2 - x = - - 1 : x = i + 2

The solutions to the quadratic equation are:

x = - i + 2, x = i + 2

5 x^{2} + 13 = 15 x

x, x^{2} - k x + 100 = 0

- 3 x^{2} + 33 = 48 x

x^{2} + 10 x = 32

4 x^{2} + 5 = - 12 x

What are the solutions to the equation (2-x)^2+1=0 ?
The solutions to the equation (2-x)^2+1=0 are x=-i+2,x=i+2
Find the zeros of (2-x)^2+1=0
The zeros of (2-x)^2+1=0 are x=-i+2,x=i+2