What are the solutions to the equation 30x^2+40=0 ?

The solutions to the equation 30x^2+40=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

Find the zeros of 30x^2+40=0

The zeros of 30x^2+40=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

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30 x^{2} + 40 = 0

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

30 x^{2} + 40 = 0

Move

40

to the right side

30 x^{2} = - 40

Divide both sides by

30

x^{2} = - \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{3}, x = - - \frac{4}{3}

- \frac{4}{3} = \frac{2}{3} i

- - \frac{4}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

4 x^{2} + 4 x = 1

120 = (2 x - 1) (x)

x^{2} - 6 = - 4 x - 6

x, z = 8 - x^{2} - y^{2}

r^{2} + 12 r + 11 = 0

What are the solutions to the equation 30x^2+40=0 ?
The solutions to the equation 30x^2+40=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i
Find the zeros of 30x^2+40=0
The zeros of 30x^2+40=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i