What are the solutions to the equation 120=(2x-1)(x) ?

The solutions to the equation 120=(2x-1)(x) are x=8,x=-15/2

Find the zeros of 120=(2x-1)(x)

The zeros of 120=(2x-1)(x) are x=8,x=-15/2

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120 = (2 x - 1) (x)

x = 8, x = - \frac{15}{2}

Decimal Notation

x = 8, x = - 7.5

Solution steps

120 = (2 x - 1) (x)

Expand

(2 x - 1) (x) : 2 x^{2} - x

120 = 2 x^{2} - x

Switch sides

2 x^{2} - x = 120

Move

120

to the left side

2 x^{2} - x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 120 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 120) = 31

x_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 2}

x = \frac{- ( - 1 ) + 31}{2 \cdot 2} : 8

x = \frac{- ( - 1 ) - 31}{2 \cdot 2} : - \frac{15}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{15}{2}

x^{2} - 6 = - 4 x - 6

x, z = 8 - x^{2} - y^{2}

r^{2} + 12 r + 11 = 0

x^{2} + 3 x - 12 = - 2

- 5 x^{2} = - 6 x^{2} - 77 + 2 x

What are the solutions to the equation 120=(2x-1)(x) ?
The solutions to the equation 120=(2x-1)(x) are x=8,x=-15/2
Find the zeros of 120=(2x-1)(x)
The zeros of 120=(2x-1)(x) are x=8,x=-15/2