What are the solutions to the equation x^2+3x-12=-2 ?

The solutions to the equation x^2+3x-12=-2 are x=2,x=-5

Find the zeros of x^2+3x-12=-2

The zeros of x^2+3x-12=-2 are x=2,x=-5

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x^{2} + 3 x - 12 = - 2

x = 2, x = - 5

Solution steps

x^{2} + 3 x - 12 = - 2

Move

2

to the left side

x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 1}, x_{2} = \frac{- 3 - 7}{2 \cdot 1}

x = \frac{- 3 + 7}{2 \cdot 1} : 2

x = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

- 5 x^{2} = - 6 x^{2} - 77 + 2 x

3 (3 x - 3)^{2} = 3

16 u^{2} + 25 b^{4} + 40 a b^{2}

6 x^{2} + 4 x - 18 = 0

x, x^{2} + 4 y^{2} + 9 z^{2} = 1

What are the solutions to the equation x^2+3x-12=-2 ?
The solutions to the equation x^2+3x-12=-2 are x=2,x=-5
Find the zeros of x^2+3x-12=-2
The zeros of x^2+3x-12=-2 are x=2,x=-5