What are the solutions to the equation -5x^2=-6x^2-77+2x ?

The solutions to the equation -5x^2=-6x^2-77+2x are x=1-2sqrt(19)i,x=1+2sqrt(19)i

Find the zeros of -5x^2=-6x^2-77+2x

The zeros of -5x^2=-6x^2-77+2x are x=1-2sqrt(19)i,x=1+2sqrt(19)i

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- 5 x^{2} = - 6 x^{2} - 77 + 2 x

x = 1 - 219 i, x = 1 + 219 i

Solution steps

- 5 x^{2} = - 6 x^{2} - 77 + 2 x

Switch sides

- 6 x^{2} - 77 + 2 x = - 5 x^{2}

Move

5 x^{2}

to the left side

- x^{2} + 2 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 77 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 77) : 419 i

x_{1, 2} = \frac{- 2 \pm 4 19 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 4 19 i}{2 ( - 1 )}, x_{2} = \frac{- 2 - 4 19 i}{2 ( - 1 )}

x = \frac{- 2 + 4 19 i}{2 ( - 1 )} : 1 - 219 i

x = \frac{- 2 - 4 19 i}{2 ( - 1 )} : 1 + 219 i

The solutions to the quadratic equation are:

x = 1 - 219 i, x = 1 + 219 i

3 (3 x - 3)^{2} = 3

16 u^{2} + 25 b^{4} + 40 a b^{2}

6 x^{2} + 4 x - 18 = 0

x, x^{2} + 4 y^{2} + 9 z^{2} = 1

(2 x - a)^{2} = 4 a^{2}

What are the solutions to the equation -5x^2=-6x^2-77+2x ?
The solutions to the equation -5x^2=-6x^2-77+2x are x=1-2sqrt(19)i,x=1+2sqrt(19)i
Find the zeros of -5x^2=-6x^2-77+2x
The zeros of -5x^2=-6x^2-77+2x are x=1-2sqrt(19)i,x=1+2sqrt(19)i