What are the solutions to the equation (2x-a)^2=4a^2 ?

The solutions to the equation (2x-a)^2=4a^2 are x=(3a)/2 ,x=-a/2

Find the zeros of (2x-a)^2=4a^2

The zeros of (2x-a)^2=4a^2 are x=(3a)/2 ,x=-a/2

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(2 x - a)^{2} = 4 a^{2}

x = \frac{3 a}{2}, x = - \frac{a}{2}

Solution steps

(2 x - a)^{2} = 4 a^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - a = 4 a^{2} : x = \frac{3 a}{2}

Solve

2 x - a = - 4 a^{2} : x = - \frac{a}{2}

The solutions to the quadratic equation are:

x = \frac{3 a}{2}, x = - \frac{a}{2}

6 x^{2} - 5 x - 2 = - 6 x^{2}

10 n^{2} = n^{2} + 16

3 x^{2} + 12 x = 7 x + 2

48 x^{2} + 132 x - 36 = 0

4 t^{2} + 4 t - 1 = 0

What are the solutions to the equation (2x-a)^2=4a^2 ?
The solutions to the equation (2x-a)^2=4a^2 are x=(3a)/2 ,x=-a/2
Find the zeros of (2x-a)^2=4a^2
The zeros of (2x-a)^2=4a^2 are x=(3a)/2 ,x=-a/2