What are the solutions to the equation factor 10n^2=n^2+16 ?

The solutions to the equation factor 10n^2=n^2+16 are n=-4/3 ,n= 4/3

Find the zeros of factor 10n^2=n^2+16

The zeros of factor 10n^2=n^2+16 are n=-4/3 ,n= 4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 n^{2} = n^{2} + 16

n = - \frac{4}{3}, n = \frac{4}{3}

Decimal Notation

n = - 1.33333 \dots, n = 1.33333 \dots

Solution steps

10 n^{2} = n^{2} + 16

Switch sides

n^{2} + 16 = 10 n^{2}

Move

10 n^{2}

to the left side

- 9 n^{2} + 16 = 0

Factor

- 9 n^{2} + 16 : - (3 n + 4) (3 n - 4)

- (3 n + 4) (3 n - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 n + 4 = 0 or 3 n - 4 = 0

Solve

3 n + 4 = 0 : n = - \frac{4}{3}

Solve

3 n - 4 = 0 : n = \frac{4}{3}

The solutions to the quadratic equation are:

n = - \frac{4}{3}, n = \frac{4}{3}

3 x^{2} + 12 x = 7 x + 2

48 x^{2} + 132 x - 36 = 0

4 t^{2} + 4 t - 1 = 0

x^{2} - 5 x - 1 = - 1

x + c = x^{2} - x - 12

What are the solutions to the equation factor 10n^2=n^2+16 ?
The solutions to the equation factor 10n^2=n^2+16 are n=-4/3 ,n= 4/3
Find the zeros of factor 10n^2=n^2+16
The zeros of factor 10n^2=n^2+16 are n=-4/3 ,n= 4/3