What are the solutions to the equation 4x^2=x^2+3 ?

The solutions to the equation 4x^2=x^2+3 are x=1,x=-1

Find the zeros of 4x^2=x^2+3

The zeros of 4x^2=x^2+3 are x=1,x=-1

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4 x^{2} = x^{2} + 3

x = 1, x = - 1

Solution steps

4 x^{2} = x^{2} + 3

Move

x^{2}

to the left side

3 x^{2} = 3

Divide both sides by

3

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

y, a y^{2} = x (a^{2} - x^{2})

x^{2} - 15 x - 39 = - 30

- 16 x^{2} = 200

x, x^{2} - 2 = 2 x - 2

3 x^{2} + 3 x + \frac{1}{2} = 0

What are the solutions to the equation 4x^2=x^2+3 ?
The solutions to the equation 4x^2=x^2+3 are x=1,x=-1
Find the zeros of 4x^2=x^2+3
The zeros of 4x^2=x^2+3 are x=1,x=-1