What are the solutions to the equation -16x^2=200 ?

The solutions to the equation -16x^2=200 are x= 5/(sqrt(2))i,x=-5/(sqrt(2))i

Find the zeros of -16x^2=200

The zeros of -16x^2=200 are x= 5/(sqrt(2))i,x=-5/(sqrt(2))i

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- 16 x^{2} = 200

x = \frac{5}{2} i, x = - \frac{5}{2} i

Solution steps

- 16 x^{2} = 200

Divide both sides by

- 16

x^{2} = - \frac{25}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{25}{2}, x = - - \frac{25}{2}

- \frac{25}{2} = \frac{5}{2} i

- - \frac{25}{2} = - \frac{5}{2} i

x = \frac{5}{2} i, x = - \frac{5}{2} i

x, x^{2} - 2 = 2 x - 2

3 x^{2} + 3 x + \frac{1}{2} = 0

\frac{1}{4} (x - 4)^{2} + 1 = 0

x^{2} - x - 8 = 2 x^{2} - 2 x - 14

x, 4 x^{2} + 11 x = - 6

What are the solutions to the equation -16x^2=200 ?
The solutions to the equation -16x^2=200 are x= 5/(sqrt(2))i,x=-5/(sqrt(2))i
Find the zeros of -16x^2=200
The zeros of -16x^2=200 are x= 5/(sqrt(2))i,x=-5/(sqrt(2))i