What are the solutions to the equation 1/4 (x-4)^2+1=0 ?

The solutions to the equation 1/4 (x-4)^2+1=0 are x=2i+4,x=-2i+4

Find the zeros of 1/4 (x-4)^2+1=0

The zeros of 1/4 (x-4)^2+1=0 are x=2i+4,x=-2i+4

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\frac{1}{4} (x - 4)^{2} + 1 = 0

x = 2 i + 4, x = - 2 i + 4

Solution steps

\frac{1}{4} (x - 4)^{2} + 1 = 0

Move

1

to the right side

\frac{1}{4} (x - 4)^{2} = - 1

Multiply both sides by

4

(x - 4)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 4 : x = 2 i + 4

Solve

x - 4 = - - 4 : x = - 2 i + 4

The solutions to the quadratic equation are:

x = 2 i + 4, x = - 2 i + 4

x^{2} - x - 8 = 2 x^{2} - 2 x - 14

x, 4 x^{2} + 11 x = - 6

x^{2} - 0.5 x + 0.5 = 0

0 = - x^{2} + 12 x

x^{2} = 6 x - 117

What are the solutions to the equation 1/4 (x-4)^2+1=0 ?
The solutions to the equation 1/4 (x-4)^2+1=0 are x=2i+4,x=-2i+4
Find the zeros of 1/4 (x-4)^2+1=0
The zeros of 1/4 (x-4)^2+1=0 are x=2i+4,x=-2i+4