What are the solutions to the equation 0=-3x^2-6x-2 ?

The solutions to the equation 0=-3x^2-6x-2 are x=-(3+sqrt(3))/3 ,x=-(3-sqrt(3))/3

Find the zeros of 0=-3x^2-6x-2

The zeros of 0=-3x^2-6x-2 are x=-(3+sqrt(3))/3 ,x=-(3-sqrt(3))/3

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0 = - 3 x^{2} - 6 x - 2

x = - \frac{3 + 3}{3}, x = - \frac{3 - 3}{3}

Decimal Notation

x = - 1.57735 \dots, x = - 0.42264 \dots

Solution steps

0 = - 3 x^{2} - 6 x - 2

Switch sides

- 3 x^{2} - 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

(- 6)^{2} - 4 (- 3) (- 2) = 23

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3}{2 ( - 3 )}, x_{2} = \frac{- ( - 6 ) - 2 3}{2 ( - 3 )}

x = \frac{- ( - 6 ) + 2 3}{2 ( - 3 )} : - \frac{3 + 3}{3}

x = \frac{- ( - 6 ) - 2 3}{2 ( - 3 )} : - \frac{3 - 3}{3}

The solutions to the quadratic equation are:

x = - \frac{3 + 3}{3}, x = - \frac{3 - 3}{3}

4 x^{2} - 3 x - 27 = 0

- 3 X^{2} + 18 X = - 30

4 (2 x - 2)^{2} = 16

x^{2} = 3 + 5 x - x^{2}

2 x^{2} - 4 x - 6 = 0

What are the solutions to the equation 0=-3x^2-6x-2 ?
The solutions to the equation 0=-3x^2-6x-2 are x=-(3+sqrt(3))/3 ,x=-(3-sqrt(3))/3
Find the zeros of 0=-3x^2-6x-2
The zeros of 0=-3x^2-6x-2 are x=-(3+sqrt(3))/3 ,x=-(3-sqrt(3))/3