What are the solutions to the equation 4(2x-2)^2=16 ?

The solutions to the equation 4(2x-2)^2=16 are x=2,x=0

Find the zeros of 4(2x-2)^2=16

The zeros of 4(2x-2)^2=16 are x=2,x=0

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4 (2 x - 2)^{2} = 16

x = 2, x = 0

Solution steps

4 (2 x - 2)^{2} = 16

Divide both sides by

4

(2 x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 2 = 4 : x = 2

Solve

2 x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 2, x = 0

x^{2} = 3 + 5 x - x^{2}

2 x^{2} - 4 x - 6 = 0

300000 = 12 x^{2} + 800 x + 40000

(x + 1)^{2} = - 6

5 x^{2} - 5 x - 169 = 2 x^{2} + x + 5

What are the solutions to the equation 4(2x-2)^2=16 ?
The solutions to the equation 4(2x-2)^2=16 are x=2,x=0
Find the zeros of 4(2x-2)^2=16
The zeros of 4(2x-2)^2=16 are x=2,x=0