What are the solutions to the equation factor 3x^2+7x+5=3x+4 ?

The solutions to the equation factor 3x^2+7x+5=3x+4 are x=-1/3 ,x=-1

Find the zeros of factor 3x^2+7x+5=3x+4

The zeros of factor 3x^2+7x+5=3x+4 are x=-1/3 ,x=-1

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3 x^{2} + 7 x + 5 = 3 x + 4

x = - \frac{1}{3}, x = - 1

Decimal Notation

x = - 0.33333 \dots, x = - 1

Solution steps

3 x^{2} + 7 x + 5 = 3 x + 4

Move

4

to the left side

3 x^{2} + 7 x + 1 = 3 x

Move

3 x

to the left side

3 x^{2} + 4 x + 1 = 0

Factor

3 x^{2} + 4 x + 1 : (3 x + 1) (x + 1)

(3 x + 1) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0 or x + 1 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 1

m^{2} = - 89

12 x^{2} - 32 x + 12 = 0

- 2 (x - 1) (x + 3) = 0

13 x^{2} = 16

u (u + 6) = 3

What are the solutions to the equation factor 3x^2+7x+5=3x+4 ?
The solutions to the equation factor 3x^2+7x+5=3x+4 are x=-1/3 ,x=-1
Find the zeros of factor 3x^2+7x+5=3x+4
The zeros of factor 3x^2+7x+5=3x+4 are x=-1/3 ,x=-1