What are the solutions to the equation factor x+12x^2=6 ?

The solutions to the equation factor x+12x^2=6 are x= 2/3 ,x=-3/4

Find the zeros of factor x+12x^2=6

The zeros of factor x+12x^2=6 are x= 2/3 ,x=-3/4

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x + 12 x^{2} = 6

x = \frac{2}{3}, x = - \frac{3}{4}

Decimal Notation

x = 0.66666 \dots, x = - 0.75

Solution steps

x + 12 x^{2} = 6

Move

6

to the left side

x + 12 x^{2} - 6 = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} + x - 6 = 0

Factor

12 x^{2} + x - 6 : (3 x - 2) (4 x + 3)

(3 x - 2) (4 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or 4 x + 3 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

4 x + 3 = 0 : x = - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{3}{4}

(x) (x) = 2 x

9 x^{2} - 2 x - 3 = 0

x, x^{2} + 4 y^{2} = 4 a y

x^{2} - 4 x - 2 = 0

x, x^{2} - 3 x y + y^{3} = 3

What are the solutions to the equation factor x+12x^2=6 ?
The solutions to the equation factor x+12x^2=6 are x= 2/3 ,x=-3/4
Find the zeros of factor x+12x^2=6
The zeros of factor x+12x^2=6 are x= 2/3 ,x=-3/4