What are the solutions to the equation 9x^2-2x-3=0 ?

The solutions to the equation 9x^2-2x-3=0 are x=(1+2sqrt(7))/9 ,x=(1-2sqrt(7))/9

Find the zeros of 9x^2-2x-3=0

The zeros of 9x^2-2x-3=0 are x=(1+2sqrt(7))/9 ,x=(1-2sqrt(7))/9

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9 x^{2} - 2 x - 3 = 0

x = \frac{1 + 2 7}{9}, x = \frac{1 - 2 7}{9}

Decimal Notation

x = 0.69905 \dots, x = - 0.47683 \dots

Solution steps

9 x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 9 ( - 3 )}{2 \cdot 9}

(- 2)^{2} - 4 \cdot 9 (- 3) = 47

x_{1, 2} = \frac{- ( - 2 ) \pm 4 7}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 7}{2 \cdot 9}, x_{2} = \frac{- ( - 2 ) - 4 7}{2 \cdot 9}

x = \frac{- ( - 2 ) + 4 7}{2 \cdot 9} : \frac{1 + 2 7}{9}

x = \frac{- ( - 2 ) - 4 7}{2 \cdot 9} : \frac{1 - 2 7}{9}

The solutions to the quadratic equation are:

x = \frac{1 + 2 7}{9}, x = \frac{1 - 2 7}{9}

x, x^{2} + 4 y^{2} = 4 a y

x^{2} - 4 x - 2 = 0

x, x^{2} - 3 x y + y^{3} = 3

- 3 x^{2} + 12 x + 4 = 0

5 x^{2} - 3 + 2 x^{2} = 4

What are the solutions to the equation 9x^2-2x-3=0 ?
The solutions to the equation 9x^2-2x-3=0 are x=(1+2sqrt(7))/9 ,x=(1-2sqrt(7))/9
Find the zeros of 9x^2-2x-3=0
The zeros of 9x^2-2x-3=0 are x=(1+2sqrt(7))/9 ,x=(1-2sqrt(7))/9