What are the solutions to the equation 5x^2-3+2x^2=4 ?

The solutions to the equation 5x^2-3+2x^2=4 are x=1,x=-1

Find the zeros of 5x^2-3+2x^2=4

The zeros of 5x^2-3+2x^2=4 are x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 3 + 2 x^{2} = 4

x = 1, x = - 1

Solution steps

5 x^{2} - 3 + 2 x^{2} = 4

Move

3

to the right side

5 x^{2} + 2 x^{2} = 7

Add similar elements:

5 x^{2} + 2 x^{2} = 7 x^{2}

7 x^{2} = 7

Divide both sides by

7

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

2 x^{2} + 12 x = 4

6 x^{2} - 7 x - 3 = 0

4 (x + 1)^{2} = 9

4 x^{2} + 268 = - 72 x

a \times a + a = 240

What are the solutions to the equation 5x^2-3+2x^2=4 ?
The solutions to the equation 5x^2-3+2x^2=4 are x=1,x=-1
Find the zeros of 5x^2-3+2x^2=4
The zeros of 5x^2-3+2x^2=4 are x=1,x=-1