What are the solutions to the equation 0=x^2+6x-10 ?

The solutions to the equation 0=x^2+6x-10 are x=-3+sqrt(19),x=-3-sqrt(19)

Find the zeros of 0=x^2+6x-10

The zeros of 0=x^2+6x-10 are x=-3+sqrt(19),x=-3-sqrt(19)

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0 = x^{2} + 6 x - 10

x = - 3 + 19, x = - 3 - 19

Decimal Notation

x = 1.35889 \dots, x = - 7.35889 \dots

Solution steps

0 = x^{2} + 6 x - 10

Switch sides

x^{2} + 6 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 10) = 219

x_{1, 2} = \frac{- 6 \pm 2 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 19}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 19}{2 \cdot 1}

x = \frac{- 6 + 2 19}{2 \cdot 1} : - 3 + 19

x = \frac{- 6 - 2 19}{2 \cdot 1} : - 3 - 19

The solutions to the quadratic equation are:

x = - 3 + 19, x = - 3 - 19

2 x^{2} + 15 x = x^{2} + 9 x

3 x^{2} - 4 x - 1

9 x^{2} - 1 = 35

2 x^{2} - 8 = - 17

3 u^{2} + 6 = - 11 u

What are the solutions to the equation 0=x^2+6x-10 ?
The solutions to the equation 0=x^2+6x-10 are x=-3+sqrt(19),x=-3-sqrt(19)
Find the zeros of 0=x^2+6x-10
The zeros of 0=x^2+6x-10 are x=-3+sqrt(19),x=-3-sqrt(19)