What are the solutions to the equation -4d^2+9d+6=3-7d ?

The solutions to the equation -4d^2+9d+6=3-7d are d=-(-4+sqrt(19))/2 ,d=(4+sqrt(19))/2

Find the zeros of -4d^2+9d+6=3-7d

The zeros of -4d^2+9d+6=3-7d are d=-(-4+sqrt(19))/2 ,d=(4+sqrt(19))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 d^{2} + 9 d + 6 = 3 - 7 d

d = - \frac{- 4 + 19}{2}, d = \frac{4 + 19}{2}

Decimal Notation

d = - 0.17944 \dots, d = 4.17944 \dots

Solution steps

- 4 d^{2} + 9 d + 6 = 3 - 7 d

Move

7 d

to the left side

- 4 d^{2} + 16 d + 6 = 3

Move

3

to the left side

- 4 d^{2} + 16 d + 3 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

1 6^{2} - 4 (- 4) \cdot 3 = 419

d_{1, 2} = \frac{- 16 \pm 4 19}{2 ( - 4 )}

Separate the solutions

d_{1} = \frac{- 16 + 4 19}{2 ( - 4 )}, d_{2} = \frac{- 16 - 4 19}{2 ( - 4 )}

d = \frac{- 16 + 4 19}{2 ( - 4 )} : - \frac{- 4 + 19}{2}

d = \frac{- 16 - 4 19}{2 ( - 4 )} : \frac{4 + 19}{2}

The solutions to the quadratic equation are:

d = - \frac{- 4 + 19}{2}, d = \frac{4 + 19}{2}

x^{2} - 250 x + 10000 = 0

5 x^{2} - 4 x - 11 = 3 x^{2}

5 x^{2} + 1 = 21

x^{2} - 8 x + 32 = 0

(5 - 1) x^{2} - 2 x - (5 + 1) = 0

What are the solutions to the equation -4d^2+9d+6=3-7d ?
The solutions to the equation -4d^2+9d+6=3-7d are d=-(-4+sqrt(19))/2 ,d=(4+sqrt(19))/2
Find the zeros of -4d^2+9d+6=3-7d
The zeros of -4d^2+9d+6=3-7d are d=-(-4+sqrt(19))/2 ,d=(4+sqrt(19))/2