What are the solutions to the equation solvefor x,h^{-1}(x)= 1/2 x^2 ?

The solutions to the equation solvefor x,h^{-1}(x)= 1/2 x^2 are x= 2/h ,x=0

Find the zeros of solvefor x,h^{-1}(x)= 1/2 x^2

The zeros of solvefor x,h^{-1}(x)= 1/2 x^2 are x= 2/h ,x=0

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solve for

x, h^{- 1} (x) = \frac{1}{2} x^{2}

x = \frac{2}{h}, x = 0

Solution steps

h^{- 1} (x) = \frac{1}{2} x^{2}

Multiply both sides by

2

\frac{2 x}{h} = x^{2}

Switch sides

x^{2} = \frac{2 x}{h}

Move

\frac{2 x}{h}

to the left side

x^{2} - \frac{2 x}{h} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - \frac{2}{h} ) \pm ( - \frac{2}{h} ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

Simplify

(- \frac{2}{h})^{2} - 4 \cdot 1 \cdot 0 : \frac{2}{h}

x_{1, 2} = \frac{- ( - \frac{2}{h} ) \pm \frac{2}{h}}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - \frac{2}{h} ) + \frac{2}{h}}{2 \cdot 1}, x_{2} = \frac{- ( - \frac{2}{h} ) - \frac{2}{h}}{2 \cdot 1}

x = \frac{- ( - \frac{2}{h} ) + \frac{2}{h}}{2 \cdot 1} : \frac{2}{h}

x = \frac{- ( - \frac{2}{h} ) - \frac{2}{h}}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = \frac{2}{h}, x = 0

5 a^{2} - 7 a - 10 = 0

2 x^{2} + 24 x + 32 = 0

x^{2} + 15 x + 54 = 0

x^{2} = 6 x + 1

r^{2} - 9

What are the solutions to the equation solvefor x,h^{-1}(x)= 1/2 x^2 ?
The solutions to the equation solvefor x,h^{-1}(x)= 1/2 x^2 are x= 2/h ,x=0
Find the zeros of solvefor x,h^{-1}(x)= 1/2 x^2
The zeros of solvefor x,h^{-1}(x)= 1/2 x^2 are x= 2/h ,x=0