What are the solutions to the equation (x-12)^2=-27 ?

The solutions to the equation (x-12)^2=-27 are x=3sqrt(3)i+12,x=-3sqrt(3)i+12

Find the zeros of (x-12)^2=-27

The zeros of (x-12)^2=-27 are x=3sqrt(3)i+12,x=-3sqrt(3)i+12

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(x - 12)^{2} = - 27

x = 33 i + 12, x = - 33 i + 12

Solution steps

(x - 12)^{2} = - 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 12 = - 27 : x = 33 i + 12

Solve

x - 12 = - - 27 : x = - 33 i + 12

The solutions to the quadratic equation are:

x = 33 i + 12, x = - 33 i + 12

0 = 4 x (1 - x)

4 a^{2} + 4 a + 1 = 0

4 x^{2} - 8 x - 11

(2 x + 1) (x + 1) = 66

6 y^{2} - 11 y - 10 = 0

What are the solutions to the equation (x-12)^2=-27 ?
The solutions to the equation (x-12)^2=-27 are x=3sqrt(3)i+12,x=-3sqrt(3)i+12
Find the zeros of (x-12)^2=-27
The zeros of (x-12)^2=-27 are x=3sqrt(3)i+12,x=-3sqrt(3)i+12