What are the solutions to the equation 4a^2+4a+1=0 ?

The solutions to the equation 4a^2+4a+1=0 are a=-1/2

Find the zeros of 4a^2+4a+1=0

The zeros of 4a^2+4a+1=0 are a=-1/2

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4 a^{2} + 4 a + 1 = 0

a = - \frac{1}{2}

Decimal Notation

a = - 0.5

Solution steps

4 a^{2} + 4 a + 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

a_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

a = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

a = - \frac{1}{2}

The solution to the quadratic equation is:

a = - \frac{1}{2}

4 x^{2} - 8 x - 11

(2 x + 1) (x + 1) = 66

6 y^{2} - 11 y - 10 = 0

x^{2} + 7 x = 44

0 = x^{2} - 14 x + 49

What are the solutions to the equation 4a^2+4a+1=0 ?
The solutions to the equation 4a^2+4a+1=0 are a=-1/2
Find the zeros of 4a^2+4a+1=0
The zeros of 4a^2+4a+1=0 are a=-1/2