What are the solutions to the equation 0=x^2-14x+49 ?

The solutions to the equation 0=x^2-14x+49 are x=7

Find the zeros of 0=x^2-14x+49

The zeros of 0=x^2-14x+49 are x=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} - 14 x + 49

x = 7

Solution steps

0 = x^{2} - 14 x + 49

Switch sides

x^{2} - 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

x = 7

The solution to the quadratic equation is:

x = 7

40 = n^{2} - 3 n

x, y^{3} + y^{2} + 5 x y + x^{2} + x + y = 0

3 t (t + 1) = 4 (t + 1)

x^{2} + 22 x + 20 = 3 x^{2}

x^{2} + 12 x + 63 = 0

What are the solutions to the equation 0=x^2-14x+49 ?
The solutions to the equation 0=x^2-14x+49 are x=7
Find the zeros of 0=x^2-14x+49
The zeros of 0=x^2-14x+49 are x=7