What are the solutions to the equation 5(2x+8)^2=80 ?

The solutions to the equation 5(2x+8)^2=80 are x=-2,x=-6

Find the zeros of 5(2x+8)^2=80

The zeros of 5(2x+8)^2=80 are x=-2,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 (2 x + 8)^{2} = 80

x = - 2, x = - 6

Solution steps

5 (2 x + 8)^{2} = 80

Divide both sides by

5

(2 x + 8)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 8 = 16 : x = - 2

Solve

2 x + 8 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = - 2, x = - 6

(3 x - 4)^{2} - 1 = 7

3 (5 x - 7)^{2} - 23 = - 17

0 = 6 x^{2}

7 v^{2} - 42 = - 35 v

3 x^{2} - 7 x - 6 = 0

What are the solutions to the equation 5(2x+8)^2=80 ?
The solutions to the equation 5(2x+8)^2=80 are x=-2,x=-6
Find the zeros of 5(2x+8)^2=80
The zeros of 5(2x+8)^2=80 are x=-2,x=-6