What are the solutions to the equation w^2+16w+36=0 ?

The solutions to the equation w^2+16w+36=0 are w=2(sqrt(7)-4),w=-2(4+sqrt(7))

Find the zeros of w^2+16w+36=0

The zeros of w^2+16w+36=0 are w=2(sqrt(7)-4),w=-2(4+sqrt(7))

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w^{2} + 16 w + 36 = 0

w = 2 (7 - 4), w = - 2 (4 + 7)

Decimal Notation

w = - 2.70849 \dots, w = - 13.29150 \dots

Solution steps

w^{2} + 16 w + 36 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 36 = 47

w_{1, 2} = \frac{- 16 \pm 4 7}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 16 + 4 7}{2 \cdot 1}, w_{2} = \frac{- 16 - 4 7}{2 \cdot 1}

w = \frac{- 16 + 4 7}{2 \cdot 1} : 2 (7 - 4)

w = \frac{- 16 - 4 7}{2 \cdot 1} : - 2 (4 + 7)

The solutions to the quadratic equation are:

w = 2 (7 - 4), w = - 2 (4 + 7)

x^{2} - 5 x - 3 = 0

3 (5 x - 10)^{2} = 27

8 x^{2} + 2 x - 6 = 0

(x - 11) (5 x + 1) = 0

x^{2} + 2 x + 15

What are the solutions to the equation w^2+16w+36=0 ?
The solutions to the equation w^2+16w+36=0 are w=2(sqrt(7)-4),w=-2(4+sqrt(7))
Find the zeros of w^2+16w+36=0
The zeros of w^2+16w+36=0 are w=2(sqrt(7)-4),w=-2(4+sqrt(7))