What are the solutions to the equation -3x^2-14x+80=0 ?

The solutions to the equation -3x^2-14x+80=0 are x=-8,x= 10/3

Find the zeros of -3x^2-14x+80=0

The zeros of -3x^2-14x+80=0 are x=-8,x= 10/3

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- 3 x^{2} - 14 x + 80 = 0

x = - 8, x = \frac{10}{3}

Decimal Notation

x = - 8, x = 3.33333 \dots

Solution steps

- 3 x^{2} - 14 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 3 ) \cdot 80}{2 ( - 3 )}

(- 14)^{2} - 4 (- 3) \cdot 80 = 34

x_{1, 2} = \frac{- ( - 14 ) \pm 34}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 34}{2 ( - 3 )}, x_{2} = \frac{- ( - 14 ) - 34}{2 ( - 3 )}

x = \frac{- ( - 14 ) + 34}{2 ( - 3 )} : - 8

x = \frac{- ( - 14 ) - 34}{2 ( - 3 )} : \frac{10}{3}

The solutions to the quadratic equation are:

x = - 8, x = \frac{10}{3}

30 u - 25 = 9 u^{2}

y, x^{2} + x y + y^{2} - 6 = 0

X^{2} - X = - 12

10 x - 4 = 5 x^{2}

(8 + v) (4 v - 5) = 0

What are the solutions to the equation -3x^2-14x+80=0 ?
The solutions to the equation -3x^2-14x+80=0 are x=-8,x= 10/3
Find the zeros of -3x^2-14x+80=0
The zeros of -3x^2-14x+80=0 are x=-8,x= 10/3