What are the solutions to the equation 6n^2=2 ?

The solutions to the equation 6n^2=2 are n= 1/(sqrt(3)),n=-1/(sqrt(3))

Find the zeros of 6n^2=2

The zeros of 6n^2=2 are n= 1/(sqrt(3)),n=-1/(sqrt(3))

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6 n^{2} = 2

n = \frac{1}{3}, n = - \frac{1}{3}

Decimal Notation

n = 0.57735 \dots, n = - 0.57735 \dots

Solution steps

6 n^{2} = 2

Divide both sides by

6

n^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{1}{3}, n = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

n = \frac{1}{3}, n = - \frac{1}{3}

x^{2} + 4 \times (- 21) = 0

4 y^{2} = - 4 y - 1

76 = 3 m^{2} + 10

b^{2} - \frac{1}{8} = (\frac{1}{4}) b

2 x - 3 = x^{2} - 2 x + 1

What are the solutions to the equation 6n^2=2 ?
The solutions to the equation 6n^2=2 are n= 1/(sqrt(3)),n=-1/(sqrt(3))
Find the zeros of 6n^2=2
The zeros of 6n^2=2 are n= 1/(sqrt(3)),n=-1/(sqrt(3))