What are the solutions to the equation a^2+12a+27=0 ?

The solutions to the equation a^2+12a+27=0 are a=-3,a=-9

Find the zeros of a^2+12a+27=0

The zeros of a^2+12a+27=0 are a=-3,a=-9

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a^{2} + 12 a + 27 = 0

a = - 3, a = - 9

Solution steps

a^{2} + 12 a + 27 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 27 = 6

a_{1, 2} = \frac{- 12 \pm 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 12 + 6}{2 \cdot 1}, a_{2} = \frac{- 12 - 6}{2 \cdot 1}

a = \frac{- 12 + 6}{2 \cdot 1} : - 3

a = \frac{- 12 - 6}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

a = - 3, a = - 9

3 x^{2} - 7 = 7 x - 1

x^{2} + 16 x + 51 = 0

x^{2} + 9 = - 40

y, x^{2} y^{2} - 2 x y^{2} + y^{2} - x = 0

5 t^{2} + 10 t - 40 = 0

What are the solutions to the equation a^2+12a+27=0 ?
The solutions to the equation a^2+12a+27=0 are a=-3,a=-9
Find the zeros of a^2+12a+27=0
The zeros of a^2+12a+27=0 are a=-3,a=-9