What are the solutions to the equation solvefor y,9x^2-4y^2-36x-16y+20=0 ?

The solutions to the equation solvefor y,9x^2-4y^2-36x-16y+20=0 are y=-(3x-2)/2 ,y=-(-3x+10)/2

Find the zeros of solvefor y,9x^2-4y^2-36x-16y+20=0

The zeros of solvefor y,9x^2-4y^2-36x-16y+20=0 are y=-(3x-2)/2 ,y=-(-3x+10)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

y, 9 x^{2} - 4 y^{2} - 36 x - 16 y + 20 = 0

y = - \frac{3 x - 2}{2}, y = - \frac{- 3 x + 10}{2}

Solution steps

9 x^{2} - 4 y^{2} - 36 x - 16 y + 20 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 y^{2} - 16 y + 9 x^{2} - 36 x + 20 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 4 ) ( 9 x ^{2} - 36 x + 20 )}{2 ( - 4 )}

Simplify

(- 16)^{2} - 4 (- 4) (9 x^{2} - 36 x + 20) : 12 (x - 2)

y_{1, 2} = \frac{- ( - 16 ) \pm 12 ( x - 2 )}{2 ( - 4 )}

Separate the solutions

y_{1} = \frac{- ( - 16 ) + 12 ( x - 2 )}{2 ( - 4 )}, y_{2} = \frac{- ( - 16 ) - 12 ( x - 2 )}{2 ( - 4 )}

y = \frac{- ( - 16 ) + 12 ( x - 2 )}{2 ( - 4 )} : - \frac{3 x - 2}{2}

y = \frac{- ( - 16 ) - 12 ( x - 2 )}{2 ( - 4 )} : - \frac{- 3 x + 10}{2}

The solutions to the quadratic equation are:

y = - \frac{3 x - 2}{2}, y = - \frac{- 3 x + 10}{2}

(x + 6)^{2} - 32 = 0

k^{2} + 5 k = - 6

x^{2} + 63 = 16 x

(5 - r) (1 - r) + 20 = 0

4 x^{2} - x - 1 = 5

What are the solutions to the equation solvefor y,9x^2-4y^2-36x-16y+20=0 ?
The solutions to the equation solvefor y,9x^2-4y^2-36x-16y+20=0 are y=-(3x-2)/2 ,y=-(-3x+10)/2
Find the zeros of solvefor y,9x^2-4y^2-36x-16y+20=0
The zeros of solvefor y,9x^2-4y^2-36x-16y+20=0 are y=-(3x-2)/2 ,y=-(-3x+10)/2