What are the solutions to the equation k^2+5k=-6 ?

The solutions to the equation k^2+5k=-6 are k=-2,k=-3

Find the zeros of k^2+5k=-6

The zeros of k^2+5k=-6 are k=-2,k=-3

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k^{2} + 5 k = - 6

k = - 2, k = - 3

Solution steps

k^{2} + 5 k = - 6

Move

6

to the left side

k^{2} + 5 k + 6 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

k_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 5 + 1}{2 \cdot 1}, k_{2} = \frac{- 5 - 1}{2 \cdot 1}

k = \frac{- 5 + 1}{2 \cdot 1} : - 2

k = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

k = - 2, k = - 3

x^{2} + 63 = 16 x

(5 - r) (1 - r) + 20 = 0

4 x^{2} - x - 1 = 5

36 x^{2} - 49 = 0

2 x^{2} - 5 x = 6

What are the solutions to the equation k^2+5k=-6 ?
The solutions to the equation k^2+5k=-6 are k=-2,k=-3
Find the zeros of k^2+5k=-6
The zeros of k^2+5k=-6 are k=-2,k=-3