What are the solutions to the equation 2x^2-5x=6 ?

The solutions to the equation 2x^2-5x=6 are x=(5+sqrt(73))/4 ,x=(5-sqrt(73))/4

Find the zeros of 2x^2-5x=6

The zeros of 2x^2-5x=6 are x=(5+sqrt(73))/4 ,x=(5-sqrt(73))/4

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2 x^{2} - 5 x = 6

x = \frac{5 + 73}{4}, x = \frac{5 - 73}{4}

Decimal Notation

x = 3.38600 \dots, x = - 0.88600 \dots

Solution steps

2 x^{2} - 5 x = 6

Move

6

to the left side

2 x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 6) = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 2}

x = \frac{- ( - 5 ) + 73}{2 \cdot 2} : \frac{5 + 73}{4}

x = \frac{- ( - 5 ) - 73}{2 \cdot 2} : \frac{5 - 73}{4}

The solutions to the quadratic equation are:

x = \frac{5 + 73}{4}, x = \frac{5 - 73}{4}

40 = 30 t - 5 t^{2}

f, f (1 - x) = x^{2} - 2 x

4 x^{2} + 8 x + 3 = a (x + b)^{2} + e

2 x^{2} = - 6 + 8 x

x^{2} + 2 x - 3 = 0

What are the solutions to the equation 2x^2-5x=6 ?
The solutions to the equation 2x^2-5x=6 are x=(5+sqrt(73))/4 ,x=(5-sqrt(73))/4
Find the zeros of 2x^2-5x=6
The zeros of 2x^2-5x=6 are x=(5+sqrt(73))/4 ,x=(5-sqrt(73))/4