What is the answer to solvefor y,yx^2+2y=5x ?

The answer to solvefor y,yx^2+2y=5x is y=(5x)/(x^2+2);\quad x\ne sqrt(2)i,x\ne-sqrt(2)i

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solvefor y,yx^2+2y=5x

solve for

y, y x^{2} + 2 y = 5 x

y = \frac{5 x}{x ^{2} + 2}; x \neq = 2 i, x \neq = - 2 i

Solution steps

y x^{2} + 2 y = 5 x

Factor

y x^{2} + 2 y : y (x^{2} + 2)

y (x^{2} + 2) = 5 x

Divide both sides by

x^{2} + 2; x \neq = 2 i, x \neq = - 2 i

y = \frac{5 x}{x ^{2} + 2}; x \neq = 2 i, x \neq = - 2 i

y, y^{2} = x^{2} + 6 x + 9

9 p^{2} + 17 p + 12 = 3 p^{2}

x^{(2)} - 4 x + 3 = 0

1 x^{2} - 4 x - 5 = 0

4 x^{2} - 5 x = - 1

What is the answer to solvefor y,yx^2+2y=5x ?
The answer to solvefor y,yx^2+2y=5x is y=(5x)/(x^2+2);\quad x\ne sqrt(2)i,x\ne-sqrt(2)i