What are the solutions to the equation 4x^2-5x=-1 ?

The solutions to the equation 4x^2-5x=-1 are x=1,x= 1/4

Find the zeros of 4x^2-5x=-1

The zeros of 4x^2-5x=-1 are x=1,x= 1/4

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4 x^{2} - 5 x = - 1

x = 1, x = \frac{1}{4}

Decimal Notation

x = 1, x = 0.25

Solution steps

4 x^{2} - 5 x = - 1

Move

1

to the left side

4 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 \cdot 1 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 4}

x = \frac{- ( - 5 ) + 3}{2 \cdot 4} : 1

x = \frac{- ( - 5 ) - 3}{2 \cdot 4} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{4}

x^{2} + 9 x + 6

2 x^{2} - 7 = 25

k, 6 x^{2} + k x + 6 = 0

8^{2} = 8 x^{2}

x^{2} - 3 x = - 3

What are the solutions to the equation 4x^2-5x=-1 ?
The solutions to the equation 4x^2-5x=-1 are x=1,x= 1/4
Find the zeros of 4x^2-5x=-1
The zeros of 4x^2-5x=-1 are x=1,x= 1/4