What are the solutions to the equation 2x^2-7=25 ?

The solutions to the equation 2x^2-7=25 are x=4,x=-4

Find the zeros of 2x^2-7=25

The zeros of 2x^2-7=25 are x=4,x=-4

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2 x^{2} - 7 = 25

x = 4, x = - 4

Solution steps

2 x^{2} - 7 = 25

Move

7

to the right side

2 x^{2} = 32

Divide both sides by

2

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

k, 6 x^{2} + k x + 6 = 0

8^{2} = 8 x^{2}

x^{2} - 3 x = - 3

x^{2} + 30 x + 221.5 = 0

2 (\frac{1}{3})^{2} + y^{2} = 1

What are the solutions to the equation 2x^2-7=25 ?
The solutions to the equation 2x^2-7=25 are x=4,x=-4
Find the zeros of 2x^2-7=25
The zeros of 2x^2-7=25 are x=4,x=-4