What are the solutions to the equation x^2-3x=-3 ?

The solutions to the equation x^2-3x=-3 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2

Find the zeros of x^2-3x=-3

The zeros of x^2-3x=-3 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2

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x^{2} - 3 x = - 3

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

Solution steps

x^{2} - 3 x = - 3

Move

3

to the left side

x^{2} - 3 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 3 : 3 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3 i}{2 \cdot 1} : \frac{3}{2} + i \frac{3}{2}

x = \frac{- ( - 3 ) - 3 i}{2 \cdot 1} : \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

x^{2} + 30 x + 221.5 = 0

2 (\frac{1}{3})^{2} + y^{2} = 1

- x^{2} - 14 x - 13 = 0

2 x^{2} - x - 16 = 16

x^{2} - 3 x - 4 = - 3 x

What are the solutions to the equation x^2-3x=-3 ?
The solutions to the equation x^2-3x=-3 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2
Find the zeros of x^2-3x=-3
The zeros of x^2-3x=-3 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2