What are the solutions to the equation 2x^2-x-16=16 ?

The solutions to the equation 2x^2-x-16=16 are x=(1+sqrt(257))/4 ,x=(1-sqrt(257))/4

Find the zeros of 2x^2-x-16=16

The zeros of 2x^2-x-16=16 are x=(1+sqrt(257))/4 ,x=(1-sqrt(257))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - x - 16 = 16

x = \frac{1 + 257}{4}, x = \frac{1 - 257}{4}

Decimal

x = 4.25780 \dots, x = - 3.75780 \dots

Solution steps

2 x^{2} - x - 16 = 16

Move

16

to the left side

2 x^{2} - x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 32 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 32) = 257

x_{1, 2} = \frac{- ( - 1 ) \pm 257}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 257}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 257}{2 \cdot 2}

x = \frac{- ( - 1 ) + 257}{2 \cdot 2} : \frac{1 + 257}{4}

x = \frac{- ( - 1 ) - 257}{2 \cdot 2} : \frac{1 - 257}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 257}{4}, x = \frac{1 - 257}{4}

x^{2} - 3 x - 4 = - 3 x

5 d^{2} - 8 d + 1 = 0

1 3^{2} + 9^{2} = c^{2}

3 x^{2} = 196

8 x^{2} = 50 x

What are the solutions to the equation 2x^2-x-16=16 ?
The solutions to the equation 2x^2-x-16=16 are x=(1+sqrt(257))/4 ,x=(1-sqrt(257))/4
Find the zeros of 2x^2-x-16=16
The zeros of 2x^2-x-16=16 are x=(1+sqrt(257))/4 ,x=(1-sqrt(257))/4