What are the solutions to the equation 3x^2=196 ?

The solutions to the equation 3x^2=196 are x=(14)/(sqrt(3)),x=-(14)/(sqrt(3))

Find the zeros of 3x^2=196

The zeros of 3x^2=196 are x=(14)/(sqrt(3)),x=-(14)/(sqrt(3))

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3 x^{2} = 196

x = \frac{14}{3}, x = - \frac{14}{3}

Decimal Notation

x = 8.08290 \dots, x = - 8.08290 \dots

Solution steps

3 x^{2} = 196

Divide both sides by

3

x^{2} = \frac{196}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{196}{3}, x = - \frac{196}{3}

\frac{196}{3} = \frac{14}{3}

- \frac{196}{3} = - \frac{14}{3}

x = \frac{14}{3}, x = - \frac{14}{3}

8 x^{2} = 50 x

y^{2} + 2 y - 8 = 0

(n + 2) (n - 4) = 27

6 - 3 y - y^{2} = 6

2 p^{2} - 11 = 61

What are the solutions to the equation 3x^2=196 ?
The solutions to the equation 3x^2=196 are x=(14)/(sqrt(3)),x=-(14)/(sqrt(3))
Find the zeros of 3x^2=196
The zeros of 3x^2=196 are x=(14)/(sqrt(3)),x=-(14)/(sqrt(3))